What is the median salary for Destructive Testing in Jacksonville?

The median salary for Destructive Testing in Jacksonville is USD 75,000 - USD 95,000 per year.

How does the Destructive Testing salary in Jacksonville compare to the national average?

The national average salary for Destructive Testing in United States is USD 81,853 - USD 120,990, while in Jacksonville it is USD 75,000 - USD 95,000.

Destructive Testing salary in United States

Destructive Testing salary in Jacksonville

Based on 2 job listings - Jacksonville, United States 2026

Average salary

$75,000 - $95,000

Median salary

$75,000 - $95,000

Lower rangeUpper range

Compare with national average

Jacksonville

Average salary

75,000 - 95,000

Median salary

75,000 - 95,000

2 job openings

United States

Average salary

81,853 - 120,990

Median salary

84,240 - 120,000

136 job openings

Other cities

Asheville6 job openings

Frederick6 job openings

Albany5 job openings

Houston5 job openings

Dracut4 job openings

Plain City4 job openings

Umatilla4 job openings

Huntsville3 job openings

Boston3 job openings

Clearfield2 job openings

Hollister2 job openings

Knoxville2 job openings

Littleton2 job openings

Manassas2 job openings

Palmdale2 job openings

Philadelphia2 job openings

Whitehall2 job openings

Allentown1 job openings

Atlanta1 job openings

Austin1 job openings

Bloomfield1 job openings

Broussard1 job openings

Burnsville1 job openings

Carlstadt1 job openings

Destructive Testing

2 job openings in Jacksonville

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Destructive Testing in Jacksonville

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The average salary for a Destructive Testing in Jacksonville, United States is USD 75,000 - USD 95,000 per year in 2026, based on 2 job listings.

Explore 2 Destructive Testing job listings in United States on BeBee, or check our salary calculator for a personalized estimate.