How much does a Fertilizer Application earn in United States?

The estimated salary for Fertilizer Application in United States ranges from USD 55,900 to USD 64,250 USD per year, depending on experience and location. Based on 356 job listings

Salary Guide

Fertilizer Application salary in United States

Based on 356 job listings - 2026

Average salary

$55,900 - $64,250

Median salary

$55,900 - $64,250

Lower rangeUpper range

Salary distribution by percentile

10th percentile$37K

25th percentile$46K

Median$56K

75th percentile$64K

90th percentile$74K

50% of professionals earn between $46,194 - $64,250 USD

The median salary is $55,900

Top cities

Houston5 job openings

Lake Geneva5 job openings

Lexington4 job openings

Atlanta3 job openings

Aurora3 job openings

Columbus3 job openings

Greenville3 job openings

Manchester3 job openings

Fertilizer Application

356 job openings

View job listings

The average salary for a Fertilizer Application in United States is USD 55,900 - USD 64,250 per year in 2026. The median salary is USD 60,075 per year, based on 356 active job listings.

The cities with the most Fertilizer Application job opportunities in United States are Houston, Lake Geneva, Lexington, Atlanta, Aurora. Houston leads with 5 job openings.

Explore 356 Fertilizer Application job listings in United States on BeBee, or check our salary calculator for a personalized estimate.