What is the median salary for Fraud Detection in Jacksonville?

The median salary for Fraud Detection in Jacksonville is USD 46,881 - USD 58,602 per year.

How does the Fraud Detection salary in Jacksonville compare to the national average?

The national average salary for Fraud Detection in United States is USD 104,950 - USD 140,228, while in Jacksonville it is USD 46,881 - USD 58,602.

Fraud Detection salary in United States

Fraud Detection salary in Jacksonville

Based on 8 job listings - Jacksonville, United States 2026

Average salary

$46,881 - $58,602

Median salary

$46,881 - $58,602

Lower rangeUpper range

Compare with national average

Jacksonville

Average salary

46,881 - 58,602

Median salary

46,881 - 58,602

8 job openings

United States

Average salary

104,950 - 140,228

Median salary

104,950 - 140,228

2,203 job openings

Other cities

New York62 job openings

Washington25 job openings

Atlanta21 job openings

Houston19 job openings

Boston17 job openings

Pittsburgh17 job openings

San Francisco17 job openings

Sacramento15 job openings

Seattle15 job openings

Los Angeles14 job openings

San Diego14 job openings

Tampa14 job openings

Austin13 job openings

Charlotte13 job openings

Philadelphia13 job openings

San Jose13 job openings

Chicago12 job openings

Louisville12 job openings

San Antonio12 job openings

Columbus9 job openings

Las Vegas9 job openings

Latham8 job openings

Phoenix8 job openings

Alexandria7 job openings

Birmingham7 job openings

Columbia6 job openings

Dallas6 job openings

Madison6 job openings

Fraud Detection

8 job openings in Jacksonville

View job listings

The average salary for a Fraud Detection in Jacksonville, United States is USD 46,881 - USD 58,602 per year in 2026, based on 8 job listings.

Explore 8 Fraud Detection job listings in United States on BeBee, or check our salary calculator for a personalized estimate.