Intervention Plan Development salary in United States

Based on 30 job listings - 2026

Average salary

$71,501 - $87,705

Median salary

$70,125 - $85,000

Lower rangeUpper range

Salary distribution by percentile

10th percentile$59K

25th percentile$66K

Median$70K

75th percentile$79K

90th percentile$84K

50% of professionals earn between $66,300 - $78,750 USD

The median salary is $70,125

Top cities

Phoenix7 job openings

Gilbert2 job openings

New York2 job openings

Philadelphia2 job openings

Bennington1 job openings

Clarksville1 job openings

Denver1 job openings

Fayetteville1 job openings

Fort Wayne1 job openings

Liberty1 job openings

Los Alamos1 job openings

Memphis1 job openings

Midlothian1 job openings

Newburgh1 job openings

Norman1 job openings

Poughkeepsie1 job openings

Salt Lake City1 job openings

Sun City West1 job openings

Town Of Clarence1 job openings

Watkinsville1 job openings

Intervention Plan Development

30 job openings

View job listings

The average salary for a Intervention Plan Development in United States is USD 71,501 - USD 87,705 per year in 2026. The median salary is USD 77,563 per year, based on 30 active job listings.

The cities with the most Intervention Plan Development job opportunities in United States are Phoenix, Gilbert, New York, Philadelphia, Bennington. Phoenix leads with 7 job openings.

Explore 30 Intervention Plan Development job listings in United States on BeBee, or check our salary calculator for a personalized estimate.